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Diese Aufgaben gibt es in ihrer Originalsprache.

BECE Mathe10 Aufgaben

BECE Mathematics practice questions

Ten objective questions in the style of the BECE Mathematics paper: LCM, fractions, percentages, proportion, area, equations, rounding, sets and number bases, each with a worked solution.

Originale Aufgaben von Studoli-Lehrkräften im Stil der Prüfung BECE. Es sind keine offiziellen Prüfungsaufgaben.

  1. Thema: Number

    1. Find the LCM of 4, 6 and 8.

    Lösung

    B. 24

    • Multiples of 8: 8, 16, 24...
    • 24 is the first multiple of 8 that is also divisible by 4 and 6.
  2. Thema: Fractions

    2. Simplify 3/4 + 1/6.

    Lösung

    B. 11/12

    • The common denominator of 4 and 6 is 12.
    • 3/4 = 9/12 and 1/6 = 2/12.
    • 9/12 + 2/12 = 11/12.
  3. Thema: Percentages

    3. Express 45% as a fraction in its lowest terms.

    Lösung

    B. 9/20

    • 45% = 45/100.
    • Divide top and bottom by 5: 9/20.
  4. Thema: Proportion

    4. If 5 pens cost GH₵ 15, how much do 8 pens cost?

    Lösung

    C. GH₵ 24

    • Cost of one pen: 15 ÷ 5 = GH₵ 3.
    • Cost of 8 pens: 8 × 3 = GH₵ 24.
  5. Thema: Mensuration

    5. Find the area of a rectangle 12 cm long and 7 cm wide.

    Lösung

    C. 84 cm²

    • Area of a rectangle = length × width.
    • 12 × 7 = 84 cm².
  6. Thema: Equations

    6. Solve 2x + 5 = 17.

    Lösung

    A. x = 6

    • Subtract 5 from both sides: 2x = 12.
    • Divide by 2: x = 6.
  7. Thema: Approximation

    7. Round 3.6478 to two decimal places.

    Lösung

    B. 3.65

    • Look at the third decimal place: 7.
    • 7 is 5 or more, so round the second decimal place up: 3.65.
  8. Thema: Sets

    8. If A = {2, 4, 6, 8}, find n(A).

    Lösung

    B. 4

    • n(A) is the number of elements in set A.
    • A has 4 elements.
  9. Thema: Mensuration

    9. Find the perimeter of a square of side 9 cm.

    Lösung

    B. 36 cm

    • A square has 4 equal sides.
    • Perimeter = 4 × 9 = 36 cm.
  10. Thema: Number bases

    10. Convert 101 (base two) to base ten.

    Lösung

    B. 5

    • Place values from the right: 1, 2, 4.
    • 101₂ = 1 × 4 + 0 × 2 + 1 × 1 = 5.
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