Esta série está disponível no idioma original.
JAMB Physics practice questions (CBT)
Fifteen objective questions in the style of the JAMB UTME Physics CBT: motion, energy, pressure, heat, gas laws, waves, lenses, electricity, radioactivity and modern physics, each with a worked solution.
Questões originais escritas por professores da Studoli no estilo da prova JAMB UTME. Não são provas oficiais.
Timed mode
15 questions in 10 minutes, one question at a time. Your answers are marked when you submit or when the time runs out.
Tema: Dimensions
1. What are the dimensions of force?
Solução
A. MLT⁻²
- Force = mass × acceleration.
- Acceleration has dimensions LT⁻², so force is MLT⁻².
Tema: Motion
2. A car starts from rest and accelerates uniformly to 20 m/s in 5 s. How far does it travel?
Solução
D. 50 m
- Average velocity = (0 + 20) ÷ 2 = 10 m/s.
- Distance = average velocity × time = 10 × 5 = 50 m.
Tema: Energy
3. Find the kinetic energy of a 2 kg body moving at 3 m/s.
Solução
C. 9 J
- KE = ½mv².
- = ½ × 2 × 3² = 9 J.
Tema: Free fall
4. A stone is dropped from a height of 20 m. How long does it take to reach the ground? (g = 10 m/s²)
Solução
B. 2 s
- h = ½gt², so t = √(2h/g).
- t = √(2 × 20 ÷ 10) = √4 = 2 s.
Tema: Momentum
5. Find the momentum of a 5 kg mass moving at 4 m/s.
Solução
A. 20 kg m/s
- Momentum = mass × velocity.
- = 5 × 4 = 20 kg m/s.
Tema: Pressure
6. Find the pressure due to water at a depth of 10 m. (Density of water = 1000 kg/m³, g = 10 m/s²)
Solução
D. 1.0 × 10⁵ Pa
- P = hρg.
- = 10 × 1000 × 10 = 100,000 Pa = 1.0 × 10⁵ Pa.
Tema: Heat
7. How much heat is needed to raise the temperature of 2 kg of water by 10 °C? (Specific heat capacity of water = 4200 J/kg K)
Solução
C. 84,000 J
- Q = mcΔθ.
- = 2 × 4200 × 10 = 84,000 J.
Tema: Gas laws
8. A gas at 100 kPa occupies 6 L. It is compressed to 2 L at constant temperature. Find its new pressure.
Solução
B. 300 kPa
- Boyle's law: P₁V₁ = P₂V₂.
- 100 × 6 = P₂ × 2, so P₂ = 300 kPa.
Tema: Waves
9. A wave has a frequency of 50 Hz and a wavelength of 2 m. Find its speed.
Solução
A. 100 m/s
- v = fλ.
- = 50 × 2 = 100 m/s.
Tema: Lenses
10. An object is placed 15 cm from a converging lens of focal length 10 cm. Find the image distance.
Solução
D. 30 cm
- 1/f = 1/u + 1/v, so 1/v = 1/10 − 1/15.
- 1/v = 3/30 − 2/30 = 1/30.
- v = 30 cm (a real image on the other side of the lens).
Tema: Electricity
11. Find the combined resistance of 6 Ω and 3 Ω connected in parallel.
Solução
C. 2 Ω
- 1/R = 1/6 + 1/3 = 1/6 + 2/6 = 3/6.
- R = 6/3 = 2 Ω.
Tema: Electrical energy
12. A 2 kW heater is used for 3 hours. How much energy does it use?
Solução
B. 6 kWh
- Energy = power × time.
- = 2 kW × 3 h = 6 kWh.
Tema: Radioactivity
13. A radioactive sample of 64 g has a half-life of 4 days. How much remains after 12 days?
Solução
A. 8 g
- 12 days ÷ 4 days = 3 half-lives.
- 64 → 32 → 16 → 8 g.
Tema: Photoelectric effect
14. Photons of energy 5 eV fall on a metal with a work function of 2 eV. Find the maximum kinetic energy of the emitted electrons.
Solução
D. 3 eV
- Einstein's equation: KEmax = hf − W.
- = 5 − 2 = 3 eV.
Tema: Transformers
15. An ideal transformer has 100 turns on the primary and 500 turns on the secondary. The primary voltage is 240 V. Find the secondary voltage.
Solução
C. 1200 V
- Vs/Vp = Ns/Np.
- Vs = 240 × 500 ÷ 100 = 1200 V.