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Matric (NSC) Matemática10 questões

Matric Mathematics practice questions

Ten Grade 12 Mathematics questions in the style of the NSC (Matric) papers: quadratics, exponents, sequences and series, calculus, analytical geometry, trigonometry and finance.

Questões originais escritas por professores da Studoli no estilo da prova Matric (NSC). Não são provas oficiais.

  1. Tema: Algebra

    1. Solve x² − 5x + 6 = 0.

    Solução

    B. x = 2 or x = 3

    • Factorise: (x − 2)(x − 3) = 0.
    • So x = 2 or x = 3.
  2. Tema: Exponents

    2. Simplify 2^(x + 2) ÷ 2^x.

    Solução

    B. 4

    • Subtract the exponents: 2^(x + 2 − x) = 2².
    • 2² = 4.
  3. Tema: Sequences

    3. For the arithmetic sequence 3, 7, 11, ..., find T₁₀.

    Solução

    A. 39

    • a = 3 and d = 4.
    • Tₙ = a + (n − 1)d, so T₁₀ = 3 + 9 × 4 = 39.
  4. Tema: Series

    4. Find the sum of the first 20 terms of 3, 7, 11, ...

    Solução

    B. 820

    • Sₙ = n/2 [2a + (n − 1)d].
    • S₂₀ = 10 × (6 + 19 × 4) = 10 × 82 = 820.
  5. Tema: Calculus

    5. If f(x) = 2x², find f′(x).

    Solução

    B. 4x

    • Bring the power down and reduce it by 1.
    • f′(x) = 2 × 2x = 4x.
  6. Tema: Analytical geometry

    6. Find the gradient of the line through (1; 2) and (3; 8).

    Solução

    B. 3

    • m = (y₂ − y₁) ÷ (x₂ − x₁).
    • m = (8 − 2) ÷ (3 − 1) = 6 ÷ 2 = 3.
  7. Tema: Trigonometry

    7. What is the exact value of sin 30°?

    Solução

    A. 1/2

    • sin 30° = 1/2 is a special angle value.
    • Learn it with sin 45° = √2/2 and sin 60° = √3/2.
  8. Tema: Analytical geometry

    8. Find the midpoint of the line joining (2; 4) and (6; 10).

    Solução

    A. (4; 7)

    • Midpoint = ((x₁ + x₂)/2 ; (y₁ + y₂)/2).
    • ((2 + 6)/2 ; (4 + 10)/2) = (4; 7).
  9. Tema: Finance

    9. R5,000 is invested at 10% per year compounded annually. What is it worth after 2 years?

    Solução

    C. R6,050

    • A = P(1 + i)ⁿ.
    • A = 5,000 × 1.1² = 5,000 × 1.21 = R6,050.
  10. Tema: Sequences

    10. For the geometric sequence 2, 6, 18, ..., find T₅.

    Solução

    C. 162

    • a = 2 and r = 3.
    • Tₙ = arⁿ⁻¹, so T₅ = 2 × 3⁴ = 2 × 81 = 162.
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