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Matric (NSC) Maths10 questions

Matric Mathematics practice questions

Ten Grade 12 Mathematics questions in the style of the NSC (Matric) papers: quadratics, exponents, sequences and series, calculus, analytical geometry, trigonometry and finance.

Original questions written by Studoli tutors in the style of the Matric (NSC) exam. They are not official past questions.

  1. Topic: Algebra

    1. Solve x² − 5x + 6 = 0.

    Solution

    B. x = 2 or x = 3

    • Factorise: (x − 2)(x − 3) = 0.
    • So x = 2 or x = 3.
  2. Topic: Exponents

    2. Simplify 2^(x + 2) ÷ 2^x.

    Solution

    B. 4

    • Subtract the exponents: 2^(x + 2 − x) = 2².
    • 2² = 4.
  3. Topic: Sequences

    3. For the arithmetic sequence 3, 7, 11, ..., find T₁₀.

    Solution

    A. 39

    • a = 3 and d = 4.
    • Tₙ = a + (n − 1)d, so T₁₀ = 3 + 9 × 4 = 39.
  4. Topic: Series

    4. Find the sum of the first 20 terms of 3, 7, 11, ...

    Solution

    B. 820

    • Sₙ = n/2 [2a + (n − 1)d].
    • S₂₀ = 10 × (6 + 19 × 4) = 10 × 82 = 820.
  5. Topic: Calculus

    5. If f(x) = 2x², find f′(x).

    Solution

    B. 4x

    • Bring the power down and reduce it by 1.
    • f′(x) = 2 × 2x = 4x.
  6. Topic: Analytical geometry

    6. Find the gradient of the line through (1; 2) and (3; 8).

    Solution

    B. 3

    • m = (y₂ − y₁) ÷ (x₂ − x₁).
    • m = (8 − 2) ÷ (3 − 1) = 6 ÷ 2 = 3.
  7. Topic: Trigonometry

    7. What is the exact value of sin 30°?

    Solution

    A. 1/2

    • sin 30° = 1/2 is a special angle value.
    • Learn it with sin 45° = √2/2 and sin 60° = √3/2.
  8. Topic: Analytical geometry

    8. Find the midpoint of the line joining (2; 4) and (6; 10).

    Solution

    A. (4; 7)

    • Midpoint = ((x₁ + x₂)/2 ; (y₁ + y₂)/2).
    • ((2 + 6)/2 ; (4 + 10)/2) = (4; 7).
  9. Topic: Finance

    9. R5,000 is invested at 10% per year compounded annually. What is it worth after 2 years?

    Solution

    C. R6,050

    • A = P(1 + i)ⁿ.
    • A = 5,000 × 1.1² = 5,000 × 1.21 = R6,050.
  10. Topic: Sequences

    10. For the geometric sequence 2, 6, 18, ..., find T₅.

    Solution

    C. 162

    • a = 2 and r = 3.
    • Tₙ = arⁿ⁻¹, so T₅ = 2 × 3⁴ = 2 × 81 = 162.
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